KS3 & GCSE Science · GCSE

Molar Volume of Gases: GCSE Chemistry Guide

One mole of any gas occupies 24 dm³ at room temperature and pressure. This GCSE guide covers molar volume, moles-to-volume conversions and worked examples.

Duke Harewood — author of AI Tutors for Key Stage 3Updated 5 min read

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Short answer

At room temperature and pressure (RTP: 20 °C, 1 atm), one mole of any gas occupies 24 dm³ (24 000 cm³). This holds whether the gas is hydrogen, oxygen or carbon dioxide — because equal moles contain the same number of particles, which at fixed temperature and pressure occupy the same volume.

At a glance

Key stage
GCSE
Subject
Chemistry
Type
How-to guide
For
Students
Read time
5 min
Last updated
21 October 2026

Where this fits

  1. Key Stage 3Years 7–9
  2. GCSEYears 10–11This article
This article is aimed at GCSE (Years 10–11), the stage after Key Stage 3 (Years 7–9).

Method at a glance

  1. Identify the molar volume
  2. Rearrange the equation
  3. Substitute and calculate
The 3 numbered steps in this article, in order.

Why do all gases occupy the same molar volume?

Gas particles are so far apart that the actual size of the molecules is negligible compared with the distance between them. At a given temperature and pressure, what determines the volume is the number of particles and their kinetic energy — not their size or mass. This is the basis of Avogadro's Law: equal volumes of gases at the same temperature and pressure contain equal numbers of molecules.

One mole of gas always contains 6.02 × 10²³ particles. At RTP those particles occupy 24 dm³, regardless of whether the gas molecules weigh 2 g/mol (hydrogen) or 44 g/mol (carbon dioxide).

What is room temperature and pressure?

The molar volume of 24 dm³ applies at:

  • Room temperature: 20 °C (293 K)
  • Pressure: 1 atmosphere (101 kPa)

These are often abbreviated as RTP (room temperature and pressure). Older texts use 24 000 cm³ or 24 L — all the same volume.

How do you convert between moles and volumes of gas?

Method at a glance

  1. Identify the molar volume. At RTP it is 24 dm³/mol (or 24 000 cm³/mol). Check whether the question uses dm³ or cm³.
  2. Rearrange the equation. Volume (dm³) = moles × 24; or moles = volume ÷ 24.
  3. Substitute and calculate. Keep units consistent throughout.

Worked example 1: moles → volume

Question: What volume of carbon dioxide (at RTP) is produced when 0.5 mol of CO₂ is formed?

Volume = moles × 24 = 0.5 × 24 = 12 dm³

Worked example 2: volume → moles

Question: A balloon contains 4.8 dm³ of oxygen at RTP. How many moles of O₂ does it contain?

Moles = volume ÷ 24 = 4.8 ÷ 24 = 0.2 mol

Worked example 3: linking to mass

Question: What mass of magnesium is needed to produce 240 cm³ of hydrogen gas at RTP?

Mg + H₂SO₄ → MgSO₄ + H₂ (1:1 mole ratio for Mg : H₂)

Step 1 — moles of H₂: 240 cm³ ÷ 24 000 cm³/mol = 0.01 mol

Step 2 — moles of Mg: same as moles of H₂ = 0.01 mol

Step 3 — mass of Mg: 0.01 × 24 = 0.24 g

How do dm³ and cm³ relate to each other?

A common source of errors is mixing units:

Unit Equivalence
1 dm³ 1000 cm³
24 dm³ 24 000 cm³
1 dm³ 1 litre (L)

If a volume is given in cm³, divide by 1000 before using the 24 dm³/mol molar volume. If a question asks for the answer in cm³, multiply by 1000 at the end.

How does this connect to reacting masses of gases?

At GCSE, you sometimes need to combine the reacting masses method with gas volumes:

  1. Use the balanced equation to find the mole ratio.
  2. Convert any solid/liquid mass to moles using moles = mass ÷ Mᵣ.
  3. Convert any gas volume to moles using moles = volume ÷ 24 (dm³).
  4. Apply the mole ratio.
  5. Convert the answer back to mass or volume as required.
Step Formula
Mass → moles moles = mass ÷ Mᵣ
Volume (dm³) → moles moles = volume ÷ 24
Volume (cm³) → moles moles = volume ÷ 24 000
Moles → mass mass = moles × Mᵣ
Moles → volume (dm³) volume = moles × 24

Frequently asked questions

Why doesn't the molar volume apply to solids and liquids?

In solids and liquids, the particles are very close together and intermolecular forces hold them near fixed positions. The volume is determined largely by the size of the particles themselves. In gases, however, the particles are about 1000 times further apart than in a liquid, and intermolecular forces are negligible. The volume of a gas is determined almost entirely by the number of particles and the kinetic energy they carry, not by molecular size — which is why all gases share the same molar volume at a given temperature and pressure.

What happens to the molar volume at different temperatures and pressures?

Molar volume increases if temperature rises (particles move faster and spread out) and decreases if pressure increases (particles are pushed closer together). At STP (standard temperature and pressure: 0 °C and 1 atm), the molar volume is approximately 22.4 dm³/mol — slightly less than 24 dm³ at RTP. Most GCSE questions use RTP; check the question carefully for which value to use.

How can I remember whether to multiply or divide by 24?

Think about what the units cancel to: volume ÷ 24 dm³/mol gives moles (dm³ ÷ dm³/mol = mol); moles × 24 dm³/mol gives volume in dm³. You can always check your answer makes sense — one mole of a gas at RTP occupies a volume similar to a 24-litre bucket, so 0.5 mol should give 12 L (a 12-litre bucket), which is reasonable.

Why do GCSE questions sometimes give volume in cm³?

Gas syringes and small reaction vessels in school labs typically deliver volumes measured in cm³, which is a more convenient unit for small quantities. Industrial applications tend to use dm³ or m³. On the GCSE paper, always note the unit given, convert to dm³ if necessary (divide by 1000), carry out the calculation, then convert the answer back to the units the question requests.


For particle-model chemistry tutoring and GCSE calculation practice, explore Professor Curie at aitutors.me.

Key terms

  • any
  • number of particles
  • kinetic energy
  • Room temperature
  • Pressure
  • RTP
  • Identify the molar volume
  • Rearrange the equation

Sources